遇见数据集

Generate Pythagorean Triples from Consecutive Odd Numbers – Ayoub Teymornejad

收藏
Zenodo2025-12-19 更新2026-05-26 收录
官方服务:

资源简介:

Abstract This paper introduces a novel, efficient, and intuitive algebraic method for generating Pythagorean triples—sets of three positive integers (a, b, c) satisfying a^2 + b^2 = c^2. The method is based on a simple selection of a single odd integer x. From this input, the complete triple is derived using the straightforward formula: a = x(x + 2), \quad b = 2(x + 1), \quad c = x^2 + 2x + 2. We provide a rigorous algebraic proof that (a, b, c) is always a valid Pythagorean triple. This approach is then generalized for any pair of odd numbers separated by a gap 2k, yielding the extended formula a = x(x+2k),\ b = 2k(x+k),\ c = x^2 + 2kx + 2k^2. The primary advantages of this method are its remarkable simplicity, requiring only one parameter, and its capacity to generate an infinite family of triples. The generated triples are inherently primitive when x is odd. Beyond its mathematical elegance, this method serves as a powerful pedagogical tool. It offers an accessible entry point into number theory, demystifies the structure of Pythagorean triples for students, and bridges intuitive exploration with formal algebraic proof. The work concludes by discussing the method's educational applications and its potential for inspiring further investigation into related number-theoretic concepts.

提供机构:
Zenodo
创建时间:
2025-12-19
二维码
社区交流群
二维码
科研交流群
商业服务