Xantphos-Type Complexes of Group 9: Rhodium versus Iridium
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Treatment of the dimer [Rh(μ-Cl)(C8H14)2]2 (1a) with 9,9-dimethyl-4,5-bis(diisopropylphosphino)xanthene [xant(PiPr2)2] leads to the d8 square-planar complex RhCl{xant(PiPr2)2} (2), whereas reaction of the iridium counterpart [Ir(μ-Cl)(C8H14)2]2 (1b) gives the d6 octahedral compound IrHCl{xant(PiPr2)[iPrPCH(Me)CH2]} (3) as a result of the intramolecular C–H bond activation of one of the isopropyl substituents of the phosphine. Stirring 2 and 3 in 0.5 N KOH solutions of 2-propanol gives rise to the formation of hydrides RhH{xant(PiPr2)2} (4) and IrH3{xant(PiPr2)2} (5), respectively. In n-octane at 60 °C, complex 2 is stable. However, compound 3 activates the alkane to give the cis-dihydride IrH2Cl{xant(PiPr2)2} (6) and a mixture of 3- and 4-octene. Complex 6 can be also obtained by the reaction of 3 with H2. Under the same conditions, 2 affords the rhodium analogue RhH2Cl{xant(PiPr2)2} (7). Compounds 2–4 react with triflic acid (HOTf) to give RhHCl(OTf){xant(PiPr2)2} (8), IrHCl(OTf){xant(PiPr2)2} (9), and RhH2(OTf){xant(PiPr2)2} (10), respectively. The related iridium derivative IrH2(OTf){xant(PiPr2)2} (11) has also been prepared by the reaction of 6 with Tl(OTf). Complexes 2, 6, and 9 have been characterized by X-ray diffraction analysis. The {xant(PiPr2)2}M skeleton is T-shaped with the metal center situated in the common vertex.
