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Formation of a Stable Complex, RuCl2(S2CPPh3)(PPh3)2, Containing an Unstable Zwitterion from the Reaction of RuCl2(PPh3)3 with Carbon Disulfide

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Figshare2016-02-13 更新2026-04-29 收录
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https://figshare.com/articles/dataset/Formation_of_a_Stable_Complex_RuCl_sub_2_sub_S_sub_2_sub_CPPh_sub_3_sub_PPh_sub_3_sub_sub_2_sub_Containing_an_Unstable_Zwitterion_from_the_Reaction_of_RuCl_sub_2_sub_PPh_sub_3_sub_sub_3_sub_with_Carbon_Disulfide/2170228
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New insight into the complexity of the reaction of the prominent catalyst RuCl2(PPh3)3 with carbon disulfide has been obtained from a combination of X-ray diffraction and 31P NMR studies. The red-violet compound originally formulated as a cationic π-CS2 complex, [RuCl­(π-CS2)­(PPh3)3]­Cl, has been identified as a neutral molecule, RuCl2(S2CPPh3)­(PPh3)2, which contains the unstable zwitterion S2CPPh3. In the absence of RuCl2(PPh3)3, there is no sign of a reaction between triphenylphosphine and carbon disulfide, although more basic trialkylphosphines form red adducts, S2CPR3. Despite the presence of an unstable ligand, RuCl2(S2CPPh3)­(PPh3)2 is remarkably stable. It survives melting at 173–174 °C intact, is stable to air, and undergoes reversible electrochemical oxidation to form a monocation. When the reaction of RuCl2(PPh3)3 with carbon disulfide is conducted in the presence of methanol, crystals of orange [RuCl­(S2CPPh3)­(CS)­(PPh3)2]­Cl·2MeOH and yellow RuCl2(CS)­(MeOH)­(PPh3)2 also form. 31P NMR studies indicate that the unsymmetrical dinuclear complex (SC)­(Ph3P)2Ru­(μ-Cl)3Ru­(PPh3)2Cl is the initial product of the reaction of RuCl2(PPh3)3 with carbon disulfide. A path connecting the isolated products is presented.
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2016-02-13
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