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Binding of the Oxo−Rhenium(V) Core to Methionine and to N-Terminal Histidine Dipeptides

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NIAID Data Ecosystem2026-03-06 收录
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https://figshare.com/articles/dataset/Binding_of_the_Oxo_Rhenium_V_Core_to_Methionine_and_to_N_Terminal_Histidine_Dipeptides/3315805
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The ReOX2(met) compounds (X = Cl, Br) adopt a distorted octahedral structure in which a carboxylato oxygen lies trans to the ReO bond, whereas the equatorial plane is occupied by two cis halides, an NH2, and an SCH3 group. Coordination of the SCH3 unit creates an asymmetric center, leading to two diastereoisomers. X-ray diffraction studies reveal that the crystals of ReOBr2(d,l-met)·1/2H2O and ReOBr2(d,l-met)·1/2CH3OH contain only the syn isomer (S−CH3 bond on the side of the ReO bond), whereas ReOCl2(d-met) and ReOCl2(d,l-met) consist of the pure anti isomer. 1H NMR spectroscopy shows that both isomers coexist in equilibrium in acetone (anti/syn ratio = 1:1 for X = Br, 3:1 for X = Cl). Exchange between these two isomers is fast above room temperature, but it slows down below 0 °C, and the sharp second-order spectra of both isomers at −20 °C were fully assigned. The coupling constants are consistent with the solid-state conformations being retained in solution. Complexes of the type [ReOX2(His-aa)]X (X = Cl, Br) are isolated with the dipeptides His-aa (aa = Gly, Ala, Leu, and Phe). X-ray diffraction work on [ReOBr2(His-Ala)]Br reveals the presence of distorted octahedral cations containing the ReO3+ core and a dipeptide coordinated through the histidine residue via the imidazole nitrogen, the terminal amino group, and the amide oxygen, the site trans to the ReO bond being occupied by the oxygen. The alanine residue is ended by a protonated carboxylic group that does not participate in the coordination. The constant pattern of the1H NMR signals for the protons in the histidine residue confirms that the various dipeptides adopt a similar binding mode, consistent with the solid-state structure being retained in CD3OD solution.

ReOX₂(met)(X=Cl、Br)类配合物呈现畸变八面体构型,其中羧基氧位于与Re=O键反式的位置,而赤道平面则由两个顺式卤原子、一个氨基(NH₂)与一个甲硫基(SCH₃)占据。甲硫基的配位会形成一个手性中心,进而生成两种非对映异构体(diastereoisomers)。X射线衍射(X-ray diffraction)研究表明,ReOBr₂(d,l-met)·1/2H₂O与ReOBr₂(d,l-met)·1/2CH₃OH的晶体仅含syn异构体(S-CH₃键位于Re=O键一侧),而ReOCl₂(d-met)与ReOCl₂(d,l-met)则仅存在anti异构体。氢核磁共振(¹H NMR)光谱显示,两种异构体在丙酮溶液中以平衡状态共存:当X=Br时,anti/syn比例为1:1;当X=Cl时比例为3:1。两种异构体间的异构化过程在室温以上速率较快,但在0℃以下会减缓;在-20℃时,两种异构体的清晰二级光谱已被完全归属。耦合常数与固态构象在溶液中得以保留的结论相符。以二肽(dipeptides)His-aa(aa=甘氨酸(Gly)、丙氨酸(Ala)、亮氨酸(Leu)及苯丙氨酸(Phe))为配体,可分离得到[ReOX₂(His-aa)]X(X=Cl、Br)型配合物。对[ReOBr₂(His-Ala)]Br的X射线衍射研究显示,其存在含Re=O³+核心的畸变八面体阳离子,二肽配体通过组氨酸残基的咪唑氮、末端氨基与酰胺氧进行配位,而与Re=O键反式的位点则由氧原子占据。丙氨酸残基末端为质子化的羧基,未参与配位。组氨酸残基质子的¹H NMR信号模式恒定,证实了各类二肽均采用相似的配位模式,这与固态结构在氘代甲醇(CD₃OD)溶液中得以保留的结论一致。
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2016-05-06
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